If V=IR and P=VI, how much power must a 3V battery provide to drive a 15 Ohm load?

To determine the power required from a 3V battery to drive a 15 Ohm load, we can start by using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

First, we can rearrange the equation to find the current (I):

I = V / R

By substituting the known values (V = 3V and R = 15 Ohms) into the equation, we get:

I = 3V / 15Ω = 0.2 A

Now that we have the current, we can find the power (P) using the formula P = VI. We have already established V is 3V and we just calculated I is 0.2 A. Therefore:

P = 3V * 0.2 A = 0.6 W

This can be expressed as a fraction:

P = 3/5 W

Thus, the power required from a 3V battery to drive a 15 Ohm load is 3/5 W. The correct answer aligns with our calculations and demonstrates the relationship between voltage, current, and power in an electrical circuit.